Equilibrium expressions and partial pressures

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SUMMARY

The discussion centers on the equilibrium expressions for the reaction 3NO (g) + H2O (l) → 2HNO3 (aq) + NO (g). Student A presents the equilibrium constant as K=[NO][HNO3]²/[NO2]³, while Student B uses K=PNO [HNO3]²/[NO2]³. Both expressions are valid as they reflect different approaches to defining K, which can vary based on the reaction equation used. Consistency in the chosen expression is crucial for accurate calculations of K values.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with equilibrium constant expressions
  • Knowledge of partial pressures in gas reactions
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of equilibrium constant expressions for various reactions
  • Learn about the impact of reaction stoichiometry on K values
  • Explore the relationship between partial pressures and concentration in equilibrium
  • Investigate how to convert between different forms of K values
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical kinetics and equilibrium analysis will benefit from this discussion.

brake4country
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Homework Statement


In considering the reaction:
3NO (g) + H2O (l) → 2HNO3 (aq) + NO (g)
student A writes the equilibrium expression as:
K=[NO][HNO3]2/[NO2]3
while student B writes:
K=PNO [HNO3]2/[NO2]3

Whose equation is correct?

Homework Equations


NA

The Attempt at a Solution


This is a multiple choice problem but I wanted to know how each student would arrive at a different value for K.
 
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I suppose you mean

3NO2(g) + H2O ↔ 2HNO3 + NO(g)

Lousy question IMHO, as both equations can be used this way or another. I prefer the first, as it is consistent, the latter would be OK with me if written as

[tex]K = \frac{P_{NO}[HNO_3]}{P_{NO_2}^3}[/tex]

Don't worry about the fact K values are different. That's normal, K value depends on the way reaction equation is written. As long as you are consistent you will get the same final result (and if you know the reaction equations converting between different values of K is not that difficult).
 
Thank you!
 

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