Equilibrium of a Spring: Force or Mass?

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SUMMARY

The equilibrium of a spring is defined as the state when the spring is in its natural uncompressed position, referred to as x=0. When a mass is applied to the spring, a new equilibrium point can be established, which simplifies the analysis of vertical oscillation problems. This new equilibrium allows the spring to oscillate at the same frequency as it would in a horizontal orientation, but around the new equilibrium position instead of the uncompressed state.

PREREQUISITES
  • Understanding of Hooke's Law and spring mechanics
  • Basic knowledge of oscillation and frequency concepts
  • Familiarity with equilibrium states in physics
  • Ability to analyze vertical versus horizontal motion
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  • Study Hooke's Law and its applications in spring mechanics
  • Learn about the principles of oscillation frequency in different orientations
  • Explore the concept of dynamic equilibrium in physics
  • Investigate vertical oscillation problems involving mass and springs
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I was just wondering, is the equilibrium of a spring when there is no force applied or when there is a mass on it and it is in equilibrium?

Thankyou.
 
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The force comes from the compression of the spring, so equilibrium point is when the spring is in it's natural uncompressed state (x=0 is defined as this point).
 
Sometimes you can define a new equilibrium point for a spring that's got a mass hanging from it. This helps simplify vertical oscillation problems because the spring still oscillates at the same frequency it would if it were horizontally oriented, but it oscillates about its "new" equilibrium rather than its uncompressed equilibrium.
 

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