A force is applied to a box 60 degrees from the horizontal. The box weights 5kg. If the force is 120N, and the surface upon which the box rests upon is frictionless, at what rate does the block accelerate?
Fnet = ma
The Attempt at a Solution
I understood the problem initially got the correct answer. The only forces are horizontal so Fcos60 = ma --> 120Ncos60/5 kg = a --> a=12
But when I looked at it again, I wasn't sure how the vertical forces canceled. Fg is 50N. So the normal force has to equal that in the opposite direction to cancel.
Down forces: mg
Up forces: mg + Fsin60
So it seems that the up forces are greater since it's mg + Fsin60 and the down is only mg..little confused.
IDK if this will allow me to show it but this picture shows all the forces:
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