Equilibrium Temperature of a Spherical Black Body Satellite

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SUMMARY

The discussion centers on calculating the equilibrium temperature (Teq) of a spherical black body satellite with a radius of 0.3 meters and an internal power generation of 3900 Watts. The initial approach utilized the Stefan-Boltzmann law, T=oT^4, but failed due to not accounting for the surface area of the satellite. The correct method involves dividing the total power by the surface area of the sphere before applying the Stefan-Boltzmann equation, leading to the correct calculation of Teq.

PREREQUISITES
  • Understanding of the Stefan-Boltzmann law
  • Knowledge of surface area calculations for spheres
  • Familiarity with thermal equilibrium concepts
  • Basic physics of power generation and heat transfer
NEXT STEPS
  • Study the Stefan-Boltzmann law in detail
  • Learn how to calculate the surface area of a sphere
  • Explore thermal equilibrium in different physical systems
  • Investigate the effects of emissivity on black body radiation
USEFUL FOR

Physicists, aerospace engineers, and students studying thermal dynamics and satellite design will benefit from this discussion.

CaptainJames
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b) Real satellites are complicated objects (see photo above). To simplify the problem, suppose the satellite is a spherical black body with a 0.3 m radius. Suppose the satellite's electronics generated 3900 Watts. What would be the equilibrium temperature, Teq, of the satellite?

Okeedoke, so I started with the equation T=oT^4. So...

3900 J=(5.67x10^-8 W/m^2K^4)T^4

T=(3900 J/(5.67x10^-8 W/m^2 K^4))^(1/4)

Which gives me an incorrect answer... any hints in the right direction?
 
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CaptainJames said:
b) Real satellites are complicated objects (see photo above). To simplify the problem, suppose the satellite is a spherical black body with a 0.3 m radius. Suppose the satellite's electronics generated 3900 Watts. What would be the equilibrium temperature, Teq, of the satellite?

Okeedoke, so I started with the equation T=oT^4. So...

3900 J=(5.67x10^-8 W/m^2K^4)T^4

T=(3900 J/(5.67x10^-8 W/m^2 K^4))^(1/4)

Which gives me an incorrect answer... any hints in the right direction?
You are given the total power but you need the power/unit area. On the Left side, divide the power by the surface area and equate that to the right side.

AM
 
Ah! Thanks a bunch, I got it.
 

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