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Homework Statement:

A beer is matured in a vessel at 5 degrees. The vessel has diameter of 5m. Top pressure is 0.1 bar g CO2. Fill level is 100%. Calculate equilibrium value for average carbonation level in beer in g/L.
Data: Atm pressure = 101.3kPa
Henrys constant for CO2 in beer at 5 deg C = 15.75 atm litre mol1
Acc due to gravity = 9.81 ms1
Beer density at 5 deg = 1010 kg m3
Mol mass of CO2 = 44 g mol1
Relevant Equations:
 Absolute pressure = Gauge press + Atm press + Hydrostatic press
Abs Pressure:
Gauge press: 1 bar G = 100,000 Pa = 0.987 atm
0.1 bar G = 0.0987 atm
Atm press = 101.3 kPa = 1 atm
Hydrostatic press: average CO2 occurs 2.5m up the vessel
(9.81 ms2)(1010kgm3)(5/2) = 24,770.25 Pa
1 Pa = 9.869x10^6 atm
24,770.25 Pa = 0.2445 atm
Abs press= 0.0987 atm + 1 atm + 0.2445 = 1.3432 atm
Henrys Law: P = KhC
1.3432 atm = 15.75 atm litre mol1 C
C = 0.0853 mol1 / L
44g CO2 in 1 mole
3.752g CO2 in 0.0853 mol1 / L
Equilibrium value = 3.752 g/L
Am i correct here please?
Gauge press: 1 bar G = 100,000 Pa = 0.987 atm
0.1 bar G = 0.0987 atm
Atm press = 101.3 kPa = 1 atm
Hydrostatic press: average CO2 occurs 2.5m up the vessel
(9.81 ms2)(1010kgm3)(5/2) = 24,770.25 Pa
1 Pa = 9.869x10^6 atm
24,770.25 Pa = 0.2445 atm
Abs press= 0.0987 atm + 1 atm + 0.2445 = 1.3432 atm
Henrys Law: P = KhC
1.3432 atm = 15.75 atm litre mol1 C
C = 0.0853 mol1 / L
44g CO2 in 1 mole
3.752g CO2 in 0.0853 mol1 / L
Equilibrium value = 3.752 g/L
Am i correct here please?