Equivalence of Two Forms of Solutions to Second Order ODEs

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Homework Help Overview

The discussion revolves around proving the equivalence between two forms of solutions to second order ordinary differential equations (ODEs), specifically focusing on the harmonic oscillator described by the equation \(\frac{d^{2}x}{dt^{2}}+\frac{k}{m}x=0\). Participants are examining the relationship between a linear combination of solutions and a phase-shifted sine/cosine function.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about the correct form of the characteristic equation and its roots. There are discussions about missing components in the proposed solutions and verification of the equations. Some participants question the validity of the second solution and its satisfaction of the differential equation.

Discussion Status

The conversation is ongoing, with participants actively questioning assumptions and interpretations of the characteristic equation. There is a mix of attempts to clarify misunderstandings and verify calculations, but no consensus has been reached regarding the equivalence of the solutions.

Contextual Notes

Some participants mention errors in their calculations and express a need for clarification on the characteristic equation. There is an acknowledgment of the complexity involved in the mathematics of the problem.

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Homework Statement


I was curious if anyone could help me prove the equivalence between the two forms of solutions to second order ODEs, one being the linear combination of two solutions and the other being the phase-shifted sin/cos function.


Homework Equations


[tex]\frac{d^{2}x}{dt^{2}}+\frac{k}{m}x=0[/tex]

[tex]x(t)=Asin(\omega t+\phi)[/tex]

[tex]x(t)=C_{1}cos(\sqrt{\frac{k}{m}}t)+C_{2}sin(\sqrt{\frac{k}{m}}t[/tex]

[tex]A[/tex] and [tex]\phi[/tex] should be treated as constants. I know that this is the differential equation for a harmonic oscillator, but I figured since it's more of how the mathematics behind it work, it belongs in this forum. If the moderator believes it should be moved, then by all means please move it.

The Attempt at a Solution


I have no idea where to start the proof for this. The second solution I wrote can be simply verified from the characteristic equation for the differential equation.

Thanks.

EDIT: I found my error. Oops. I wrote it as r^2 + (k/m)r. Thats what I get for doing math at 3AM, lol.
 
Last edited:
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You're missing the second exponential in the 2nd equation.
 
Pengwuino said:
You're missing the second exponential in the 2nd equation.

Hm? Which exponential? I got roots of 0 and -k/m for that differential equation's characteristic equation. I did forget the negative sign to the -k/m though.
 
Check the roots again, the characteristic equation should be [tex]\lambda ^2 + \frac{k}{m} = 0[/tex]. Assuming k>0, you have imaginary roots giving a positive and negative exponential solution.
 
I don't think the second solution satisfies the equation.

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Last edited by a moderator:
nickmai123 said:

Homework Statement


I was curious if anyone could help me prove the equivalence between the two forms of solutions to second order ODEs, one being the linear combination of two solutions and the other being the phase-shifted sin/cos function.


Homework Equations


[tex]\frac{d^{2}x}{dt^{2}}+\frac{k}{m}x=0[/tex]

[tex]x(t)=Asin(\omega t+\phi)[/tex]

[tex]x(t)=C_{1}+C_{2}e^{-\frac{k}{m}t}[/tex]

[tex]A[/tex] and [tex]\phi[/tex] should be treated as constants. I know that this is the differential equation for a harmonic oscillator, but I figured since it's more of how the mathematics behind it work, it belongs in this forum. If the moderator believes it should be moved, then by all means please move it.

The Attempt at a Solution


I have no idea where to start the proof for this. The second solution I wrote can be simply verified from the characteristic equation for the differential equation.

Thanks.

nickmai123 said:
Hm? Which exponential? I got roots of 0 and -k/m for that differential equation's characteristic equation. I did forget the negative sign to the -k/m though.
Then you've either got the wrong characteristic equation or you have solved it incorrectly. Neither 0 nor -k/m satisfy the characteristic equation for this d.e.

Please show your work.
 
HallsofIvy said:
Then you've either got the wrong characteristic equation or you have solved it incorrectly. Neither 0 nor -k/m satisfy the characteristic equation for this d.e.

Please show your work.

Got it. Thanks.
 
Oh, that's not fair! Show your work so we can all laugh at your mistake and feel superior!

(Some silly little arithmetic or algebra mistake.)
 
HallsofIvy said:
Oh, that's not fair! Show your work so we can all laugh at your mistake and feel superior!

(Some silly little arithmetic or algebra mistake.)

Haha no i just added an r for the term (k/m)x. I took DE my sr year in high school, so most of it's begun to leave me. I have a feeling it's going to come back bite me in the butt when I take circuits... sigh.
 

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