Equivalence point concentration/number of moles

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SUMMARY

The discussion focuses on calculating the concentration of reactants and products at the equivalence point of the titration between Fe[3+] and V[2+]. Given 0.1000 M solutions, the equilibrium constant (Keq) is established as 2.23 x 10^17. At the equivalence point, the concentrations of V[3+] and Fe[2+] are determined to be 0.0500 M, derived from the initial concentration divided by 2 due to the 1:1 mole ratio and the total volume of the solution doubling during the titration process.

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drcasey
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Homework Statement


Fe[3+]+V[2+]-->Fe[2+]+V[3+]

If you start with 0.1000 M solutions and the first-named species is the titrant, what will be
the concentration of each reactant and product at the equivalence point of the titrations above? Assume that there is no change in [H+] during the titration.

Homework Equations



Keq=[V3+][Fe2+]/[V2+][Fe3+]=2.23X10^17


The Attempt at a Solution



I believe V2+ and Fe3+ will be the same at the equivalence points since that is the definition of the analyte and titrant. However, I was told that the V3+ and Fe2+ concentration is 0.1000/2. Could someone please explain why it is divided by 2 and not just 0.1000? Thank you

 
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Stoichiometry should be enough. Write the balanced reaction. You are using 1 to 1 mole ratio for the reaction. How does this relate to volume of titrant and volume of analyte solution? The resulting volume, if both concentrations are 0.1000, should be...? Think... you will see.
 
Ok just to make sure. The total volume will be 2L? Because of that, we take 0.1000mol/2?
 
drcasey said:
Ok just to make sure. The total volume will be 2L? Because of that, we take 0.1000mol/2?

Yes, just a simple dilution.
 

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