Equivalence point concentration/number of moles

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Discussion Overview

The discussion revolves around the calculation of concentrations at the equivalence point in a titration involving the reaction between Fe[3+] and V[2+]. Participants are exploring the stoichiometry of the reaction and the implications of dilution on the concentrations of reactants and products at the equivalence point.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that at the equivalence point, the concentrations of V[2+] and Fe[3+] will be equal, as this is the definition of the analyte and titrant.
  • Another participant suggests that the concentrations of V[3+] and Fe[2+] should be calculated as 0.1000/2, prompting a request for clarification on this division.
  • A participant emphasizes the importance of stoichiometry and the balanced reaction, indicating that a 1:1 mole ratio is used for the reaction.
  • There is a question about the total volume of the solution at the equivalence point, with a participant suggesting it will be 2L, which leads to the reasoning for dividing the concentration by 2.
  • One participant confirms that the dilution is a simple process, implying that the concentration changes are due to the increase in total volume.

Areas of Agreement / Disagreement

Participants generally agree on the stoichiometric principles involved, but there is some uncertainty regarding the specific calculations and the implications of dilution on the concentrations of the products at the equivalence point.

Contextual Notes

Participants have not fully resolved the assumptions regarding the total volume and how it affects the concentration calculations at the equivalence point.

Who May Find This Useful

Students and individuals interested in titration calculations, stoichiometry, and chemical equilibria may find this discussion relevant.

drcasey
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Homework Statement


Fe[3+]+V[2+]-->Fe[2+]+V[3+]

If you start with 0.1000 M solutions and the first-named species is the titrant, what will be
the concentration of each reactant and product at the equivalence point of the titrations above? Assume that there is no change in [H+] during the titration.

Homework Equations



Keq=[V3+][Fe2+]/[V2+][Fe3+]=2.23X10^17


The Attempt at a Solution



I believe V2+ and Fe3+ will be the same at the equivalence points since that is the definition of the analyte and titrant. However, I was told that the V3+ and Fe2+ concentration is 0.1000/2. Could someone please explain why it is divided by 2 and not just 0.1000? Thank you

 
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Stoichiometry should be enough. Write the balanced reaction. You are using 1 to 1 mole ratio for the reaction. How does this relate to volume of titrant and volume of analyte solution? The resulting volume, if both concentrations are 0.1000, should be...? Think... you will see.
 
Ok just to make sure. The total volume will be 2L? Because of that, we take 0.1000mol/2?
 
drcasey said:
Ok just to make sure. The total volume will be 2L? Because of that, we take 0.1000mol/2?

Yes, just a simple dilution.
 

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