Sorry that was a typo in my post. Meant to say capacitance.NascentOxygen said:
Also, that is how the problem was given. I am not sure if that is a mistake or meant to be there. But then again, inductors have a different symbol, so I guess that needs to be changed. Also, what is the point of telling me all the voltages across those capacitors? Will I need that to find the voltage later? Or do I find the voltage using only the equivalent capacitance?
Ok, I'll try both and see if I can get it.NascentOxygen said:
I got 16.3 uF for my equivalent capacitance. I'm not sure how I can find the voltage using that though. I'm not sure how to do it separately eitherNascentOxygen said:
Is that how you add voltages? What if you reach a junction with voltages? How would you treat that? Also, it looks like some of the capacitors were not labeled with a voltage, like 5uF and 24uF. Should I just ignore those or is there a way to find the voltages across those capacitors?NascentOxygen said:
Yes. In any loop, the net addition of voltages should be 0. This is according to KVL.Marcin H said:
Think harderMarcin H said:
! There's a way and I'm pretty sure you'll see it if you looked at the arrangement carefully..cnh1995 said:Think harder
If you are still confused, use this.cnh1995 said:
Ok so if I wanted to find the voltage for the 5uF I would use KVL for the top box and it would be +10V -V5 =0. But how do I find the voltage across that capacitor? Is there an equation for that? One that relates voltage and capacitance? I don't know the energy stored or the charge, so I'm not sure how I can find the voltage.cnh1995 said:
Doesn't that give V5=10V? This is the voltage across the 5μF capacitor.Marcin H said:
So once I get those missing voltages (10V for V5 and 5V for V24) how would I get the voltage across the terminals?cnh1995 said:
This is what NQ said, but I'm not sure how. What do I do when I get to a junction or if I have voltages in parallel, like the box on top? Is there a way to add voltages in parallel? I think if they are in series you just add them together.
Choose any loop containing the terminals and have a "KVL walk" along it.Marcin H said:
Ohhhhhhhhh.cnh1995 said:
I don't know why I am overthinking this so much. So much facepalm. 25V across the terminal.Right.Marcin H said:Ohhhhhhhhh.
Equivalent capacitance is the total capacitance of a circuit or system with multiple capacitors connected in either series or parallel. In series, the equivalent capacitance is calculated by adding the reciprocal of each individual capacitance and taking the reciprocal of the sum. In parallel, the equivalent capacitance is simply the sum of all individual capacitances.
Equivalent capacitance affects the voltage in a circuit by reducing the overall amount of voltage across each individual capacitor. In a series circuit, the voltage across each capacitor is divided among them, and in a parallel circuit, the voltage across each capacitor is equal.
When capacitors are connected in series, the equivalent capacitance decreases because the total distance between the plates is increased. When capacitors are connected in parallel, the equivalent capacitance increases because the total distance between the plates is decreased.
Yes, the equivalent capacitance of a circuit can be greater than the individual capacitance of one of the capacitors when they are connected in parallel. This is because the total distance between the plates is decreased, resulting in a greater capacitance.
The placement of capacitors in a circuit, whether in series or parallel, affects the equivalent capacitance. When capacitors are connected in series, the equivalent capacitance decreases, while in parallel, it increases. Additionally, the order in which the capacitors are connected can also affect the equivalent capacitance.