Equivalent Capacitance with Kirchhoff's Laws

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Homework Statement



Circuit schematic of a bridge network with terminals a and b on the left and right; capacitors labeled 2 F (upper left), 3 F (upper right), 5 F (center vertical branch), 1 F (lower left) and 4 F (lower right).


So that is my problem

I know that I have to use Kirchhoff's Laws to find the equivalent capacitance. I am just suck on how to set up those equations. I know how to do it with resistors, using V= IR. But I don't know where to use the current here, since capacitors are C = Q/V.

Any help?
 
There might be more than one way to go about this problem. But I think one way that might work out nicely is to convert each capacitor to its impedance, Z. In other words, analyze the circuit in the s-domain or phasor domain (a.k.a. Fourier domain, a.k.a. jω domain). (The s-domain might be the simplest.)

That way you can use Kirchhoff's Laws noting that V = IZ.