I Escape from Two Black Holes? Solve the Mystery!

Aerodyn
Messages
4
Reaction score
1
Hello everyone,

Imagine the following situation:
  • You are inside the events horizon of a static black hole (called BH1)
    • Now, due to the bended space-time, your future points to be inside the event horizon until eternity (You will never be outside)
  • Now, a second static black hole (BH2), similar to BH1 "appears" (for whatever reason) in the nearby, outside the events horizon of BH1, and simetrycally positioned for me, comparing to BH1 center, So:
  • BH2 ----- Me ----- BH1
    • My question is: Is there a way that BH2 can bend space time in the opposite direction than BH1, in a manner that both effects are cancelled, or reduced in a manner that now I am outside the events horizon of any of the black holes? and now i could come back home safely
In other words, If I am symetrically positioned between 2 black holes (but in a manner that if one of them was not there, i would be inside the events horizon of the other one), can I escape from them?

Thanks in advance for your support witht this oneAerodyn
 
Last edited:
Physics news on Phys.org
No. Once you are in an event horizon you are stuck there, no exceptions.
 
Aerodyn said:
  • Now, a second static black hole (BH2), similar to BH1 "appears" (for whatever reason) in the nearby, outside the events horizon of BH1, and simetrycally positioned for me, comparing to BH1 center
You cannot just "poof" a black hole into existence. You can "collapse" a black hole into existence if you have enough stress-energy in a sufficiently compact region. It appears that having accidentally stepped into the first black hole, you have also fallen into a collapsing dust cloud as that cloud has formed an event horizon and as that event horizon has swept past and engulfed you.

Possibly your eyebrows have been singed in the process. It can get crowded on an accretion disc.

In any case, you are now inside the newly merged single black hole.
 
  • Like
Likes Rene Dekker and Ibix
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
Back
Top