Escape Velocity for Moon: Is the Equation Wrong?

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SUMMARY

The discussion centers on the calculation of the escape velocity for the Moon, specifically addressing the equation v,escape = (2*mu/r)^(1/2), where mu = G*M. It is established that the original source incorrectly presents the equation by omitting the factor of 2 in front of mu = G*M, leading to confusion with the orbital speed calculation. To accurately determine the escape speed, one must multiply the orbital speed by the square root of two. This clarification is crucial for understanding the distinction between escape velocity and orbital speed.

PREREQUISITES
  • Understanding of gravitational constant (G) and mass (M) in physics
  • Familiarity with the concept of escape velocity
  • Knowledge of circular orbital motion
  • Basic algebra for manipulating equations
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  • Study the derivation of escape velocity equations in classical mechanics
  • Explore the differences between escape velocity and orbital speed
  • Learn about gravitational potential energy and its relation to escape velocity
  • Investigate the implications of escape velocity in space missions
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Students of physics, aerospace engineers, and anyone interested in celestial mechanics and space exploration.

eurekameh
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v,escape = (2*mu/r)^(1/2), where mu = G*M. What I'm asking is if this page is wrong about calculating the escape velocity for the moon. They seem to have the equation wrong (missing 2 in front of mu = G*M,moon).

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If you study the text closely you'll see that they're calculating the orbital speed for a circular orbit just above the Moon's surface, not the escape speed. Multiply by root two to get the escape speed.
 
Ah, somehow missed it. Thanks.
 

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