Estimate the mass of the Coma cluster

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SUMMARY

The mass of the Coma cluster of galaxies can be estimated using the virial theorem, specifically the formula M = 3Bσ²R/nG, where σ = 977 km/s, R = 3 Mpc, B = 1, and n = 1 for an isothermal sphere model. The calculation yields a mass of approximately 1.997 x 1015 solar masses. For a constant density model, the value of n changes to 3/5, which would require substituting this value into the mass formula to assess the impact on the estimated mass. The discussion confirms that the assumptions of isotropic motion and identical galaxies are crucial for this calculation.

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Homework Statement


Use the results we derived in class based on the virial theorem to estimate the mass of
the Coma cluster of galaxies, which has a radial velocity dispersion of o = 977 km s1
and a radius R = 3 Mpc. You can assume an isothermal sphere model for the mass
distribution and that the measured radial velocity dispersion is based on isotropic
orbits of identical galaxies.


Homework Equations


M=3B/n (Ro2/G


The Attempt at a Solution


I found this formula in my notes said it was the virial mass estimate so would i just plug in what i have into this? Seems too easy that's why I am asking if i have to do something else.
B and n would equal to 1 because its a isothermal sphere
 
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The answer should be very simple... this is not how I would have done it however.
What are B and n?

I would just use the virial theorem... what does the virial theorem state?
 
Hey in the class notes they did use virial theorem and than sub potential and kinetic to get that formula i said idk what B and N are didnt fully read the notes but said when its a isothermal sphere that b=n=1
 
Okay, well in general the virial theorem let's you relate the time average kinetic energy to the potential energy. For the case of gravity it says that:
<br /> &lt;T&gt; = -\frac{1}{2} &lt;U&gt;<br />
So if you plug in equations for kinetic and potential energies... what do you get?
 
well you get 3Bmo-nGM2/R=0
Was told that kinetic energy is 3/2BMo2
"We have made two assumptions: the motion is isotropic, and the stars are identical. Dropping
those assumptions... where B is a dimensionless factor of order unity (e.g., b = 1 if we are considering isotropic orbits of identical particles).
then potentail is -n(GM2 /R)
where n is a dimensionless factor of order unity that depends on the density profile (e.g.,
n = 1 for an isothermal sphere, and n = 3/5 for a constant density sphere)

So from 3Bmo-nGM2/R=0 just solve for M and you get 1/m=nG/3o2RB
than just flip it to gte m=3BRo2/nG
 
got the mass as 1.997e15 solar mass which seems right it also asks about .."if you used a constant density model" If the mass will increase or what looking in the note found that ... n = 3/5 for a constant density sphere so i am guess just replace the 1 with 3/5 in the formula i got before right? or is there something more?
 
This isn't quite the virial theorem I'm used to... but it sounds like you're doing it exactly right---based on the prescription you've been given. The answer shouldn't be any more complicated.
 
kk thxs for the help
 

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