Euler/Riemann Point of Departure in Riemann's 1859 paper containing RH

  • Context: MHB 
  • Thread starter Thread starter Greg
  • Start date Start date
  • Tags Tags
    Paper Point
Click For Summary
SUMMARY

The discussion centers on Riemann's 1859 paper "On the Number of Primes Less than a Given Magnitude," where he introduces the Euler product formula for the Riemann zeta function, represented as $$\prod\frac{1}{1-\frac{1}{p^s}}=\sum\frac{1}{n^s}$$. In this equation, $p$ denotes all prime numbers and $n$ represents all natural numbers. The convergence of this expression defines the complex variable function $\zeta(s)$. Participants seek methods to prove this foundational equation.

PREREQUISITES
  • Understanding of complex analysis, specifically functions of a complex variable.
  • Familiarity with prime number theory and the distribution of primes.
  • Knowledge of infinite series and products in mathematical analysis.
  • Basic understanding of the Riemann zeta function and its significance in number theory.
NEXT STEPS
  • Research the proofs of the Euler product formula for the Riemann zeta function.
  • Study the implications of the Riemann Hypothesis on prime number distribution.
  • Explore advanced topics in complex analysis relevant to $\zeta(s)$.
  • Examine historical context and mathematical significance of Riemann's 1859 paper.
USEFUL FOR

Mathematicians, number theorists, and students of complex analysis interested in the foundational aspects of prime number theory and the Riemann Hypothesis.

Greg
Gold Member
MHB
Messages
1,377
Reaction score
0
In his 1859 paper entitled "On the Number of Primes Less than a Given Magnitude", Riemann gives as his point of departure the equation

$$\prod\frac{1}{1-\frac{1}{p^s}}=\sum\frac{1}{n^s}$$[/size]

where $p$ is all primes and $n$ is all natural numbers. The function of the complex variable $s$, wherever these expressions converge, is called by Riemann $\zeta(s)$.

Any thoughts on how to prove this equation?

All comments welcome. :)
 
Mathematics news on Phys.org
It is called the Euler product formula for the Riemann zeta function.

Wiki gives 2 proofs here.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
1
Views
4K
Replies
4
Views
6K