Evacuation of a liquid-vapor water mixture

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SUMMARY

The discussion centers on the dynamics of a liquid-vapor water mixture in a vessel at 3000 kPa. When the valve is opened, only liquid water drains, causing the gas volume above to increase. To maintain the vapor pressure at this temperature, water must evaporate at the same rate that liquid flows out, ensuring the volume of water inside the control volume remains constant. This scenario highlights the relationship between liquid drainage and vapor pressure equilibrium in thermodynamic systems.

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  • Understanding of thermodynamic principles, particularly phase changes.
  • Familiarity with vapor pressure concepts, specifically at 3000 kPa.
  • Knowledge of fluid dynamics related to liquid and gas interactions.
  • Basic grasp of control volume analysis in thermodynamic systems.
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TL;DR
evacuation of a liquid-vapor water mixture
suppose i have liquid and vapor water inside a vessel at say 3000kPa, then i suddenly open the valve, as the water (liquid) flows out the vessel (control volume) is water inside the cv evaporating at the same rate liquid flows out? so the volume of water inside the cv remains constant?
 
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3000 kPa is the vapour pressure of water at that temperature.
The valve at the bottom drains liquid water only.
As the liquid is removed, the gas volume above rises.
Water must evaporate to maintain the partial pressure.
 

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