Evaluate in terms of powers of primes

[luigihs]

3³ x 4²
__________________________ =
2 x 3^-3 x 16

3^{3-(-3) = 6}
16 = 4² ... 4^{2-2 = 0}

so.. 3⁶ x 2 <-- answer I guess I am not sure

 

[Infinitum]

3³ x 4²
__________________________ =
2 x 3^-3 x 16

3^{3-(-3) = 6}
16 = 4² ... 4^{2-2 = 0}

so.. 3⁶ x 2 <-- answer I guess I am not sure

How did the 2 in the denominator come up in the numerator??

The rest is correct, though.

 

[luigihs]

so the answer is 3^6 / 2 ??

 

[Infinitum]

so the answer is 3^6 / 2 ??

Yes, or 3⁶2^-1.

 

[luigihs]

Ok Cheers :)

 

[luigihs]

Im sorry have another question is kinda the similar .
Simplify the following expressions:

2^3x 4^x or 2^2x
_________________________________________ =
16^x or 2^4x

2^{3x+2x = 5x} = 2^5x / 2^4x = 2^x

 

[Infinitum]

Im sorry have another question is kinda the similar .
Simplify the following expressions:

2^3x 4^x or 2^2x
_________________________________________ =
16^x or 2^4x

2^{3x+2x = 5x} = 2^5x / 2^4x = 2^x

That's correct too.

 

[luigihs]

ok thanks :)