MHB Evaluate Trig Expressions....Part 1

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Trig
AI Thread Summary
The discussion focuses on evaluating trigonometric expressions, specifically sin 210° and sin (-210°), using a textbook method. For sin 210°, the reference angle is correctly identified as 30°, leading to the evaluation of sin 210° as -1/2 due to its position in Quadrant III. In contrast, for sin (-210°), the coterminal angle is 150°, with a reference angle of 30° in Quadrant II, resulting in sin (-210°) being 1/2. Participants inquire about formulas for determining reference and coterminal angles in trigonometry. The thread emphasizes the importance of understanding reference angles and their signs based on quadrant locations.
mathdad
Messages
1,280
Reaction score
0
Evaluate the trig expressions using the method shown in the textbook. Steps A through C show the method given in the textbook.

1. sin 210°

A. We are told to graph sin 210°. We are in Quadrant 3.

B. Find the reference angle R.

R = 270° - 210°

R = 60°

C. Evaluate sin R.

sin 60° = -sqrt{3}/2

Book's answer is -1/2.

2. sin (-210°)

A. We are told to graph sin (-210°).
We are in Quadrant 2.

B. Find the reference angle R.

R = -270° - (-210°)

R = -270° + 210°

R = -60

C. Evaluate sin R

sin (-60°) = sqrt{3}/2

Book's answer is 1/2.
 
Mathematics news on Phys.org
1. reference angle for 210 is 30 degrees, not 60. sin(30) = 1/2, but since the reference angle is in quad III where sine is negative, sin(210) = -1/2

2. -210 is coterminal with 150

reference angle is 30 in quad II where sine is positive

sin(30) = 1/2
 
skeeter said:
1. reference angle for 210 is 30 degrees, not 60. sin(30) = 1/2, but since the reference angle is in quad III where sine is negative, sin(210) = -1/2

2. -210 is coterminal with 150

reference angle is 30 in quad II where sine is positive

sin(30) = 1/2

Is there a formula(s) for finding the reference angle and coterminal angle in trigonometry?
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Back
Top