MHB Evaluating $f'(1)$ for $f(x)=7x-3+\ln(x)$

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karush
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If $f(x)=7x-3+\ln(x),$ then $f'(1)=$
$(A)\, 4\quad (B)\: 5\quad (C)\, 6\quad (D)\,7\quad (E)\,8$
since
$$f'(x)=7+\dfrac{1}{x}$$
so then
$$f'(1)=7+\dfrac{1}{1}=7+1=8\quad (E)$$

ok kinda an easy one but typos and suggestions possible
 
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I don't see a question here. If you are asking if your solution is correct, yes it is.
 

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