Evaluating $f'(1)$ for $f(x)=7x-3+\ln(x)$

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SUMMARY

The discussion focuses on evaluating the derivative of the function \( f(x) = 7x - 3 + \ln(x) \) at the point \( x = 1 \). The derivative \( f'(x) \) is calculated as \( f'(x) = 7 + \frac{1}{x} \). Substituting \( x = 1 \) yields \( f'(1) = 7 + 1 = 8 \). Therefore, the correct answer is (E) 8.

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karush
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If $f(x)=7x-3+\ln(x),$ then $f'(1)=$
$(A)\, 4\quad (B)\: 5\quad (C)\, 6\quad (D)\,7\quad (E)\,8$
since
$$f'(x)=7+\dfrac{1}{x}$$
so then
$$f'(1)=7+\dfrac{1}{1}=7+1=8\quad (E)$$

ok kinda an easy one but typos and suggestions possible
 
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