Evaluating "iarray[i] < 0 && isigned" in C: Meaning Explained

[vorcil]

Homework Statement

in this statement

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?

Homework Equations

The Attempt at a Solution

 

[LCKurtz]

Homework Statement

in this statement

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?
/b]

I would think isigned must be a pointer and *isigned is the value stored at the address pointed to. So it isn't isigned which is 0 or 1, it is that value at that address that is. The && operator performs a logical AND interpreting that 1 or 0 as TRUE or FALSE.

 

[vorcil]

Cheers matey potatey

 

[NascentOxygen]

if (iarray < 0 && *isigned)

How do I evaluate that

the code is in c

isigned is either 0 or 1

does it mean that for each value in the array that is less than 0 AND for each value in the array that is less than isigned

or does it mean for each value in the array AND a some other statement

&& isigned (where isigned is either 0 or 1)

what does it mean?

This is not a looping statement. This if statement looks at only one element in the array.

The && is performed last, after iarray < 0 is evaluated. So it's equal to:
if ((iarray < 0) && *isigned)

Also, unless the first condition evaluates as true, then whatever isigned points to is not considered. So isigned need not point anywhere, not until iarray < 0 becomes true (at least as far as evaluation of this statement is concerned).