MHB Evaluating $m^4-18m^2-8m$ Given $p,\,q,\,r$

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The discussion focuses on evaluating the expression $m^4-18m^2-8m$, where $m=\sqrt{p}+\sqrt{q}+\sqrt{r}$ and $p, q, r$ are the roots of the polynomial $x^3-9x^2+11x-1=0$. Participants share methods for calculating the value of $m$, utilizing properties of the roots and symmetric sums. The conversation highlights the importance of understanding root relationships and polynomial identities in simplifying the expression. Ultimately, the evaluation leads to a specific numerical result, showcasing the collaborative effort in solving the problem. The thread emphasizes mathematical problem-solving techniques in algebra.
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Let $p,\,q,\,r$ be the roots of $x^3-9x^2+11x-1=0$ and let $m=\sqrt{p}+\sqrt{q}+\sqrt{r}$.

Evaluate $m^4-18m^2-8m$.
 
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Re: Find m^4-18m^2-8m

anemone said:
Let $p,\,q,\,r$ be the roots of $x^3-9x^2+11x-1=0$ and let $m=\sqrt{p}+\sqrt{q}+\sqrt{r}$.

Evaluate $m^4-18m^2-8m$.

We have

$\displaystyle m^2 = p + q + r + 2(\sqrt{pq} + \sqrt{qr} + \sqrt{rp}) = 9 + 2(\sqrt{pq} + \sqrt{qr} + \sqrt{rp})$.

Thus

$\displaystyle (m^2-9)^2 = 4[pq + qr + rp + 2(\sqrt{p(pqr)} + \sqrt{q(pqr)} + \sqrt{r(pqr)})]$
$\displaystyle = 4[11 + 2(\sqrt{p} + \sqrt{q} + \sqrt{r})]$
$\displaystyle = 44 + 8m$.

Since $(m^2 - 9)^2 = m^4 - 18m^2 + 81$, we obtain $m^4 - 18m^2 + 81 = 44 + 8m$, or

$\displaystyle m^4 -18m^2 - 8m = -37$.
 
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Awesome, Euge! Thanks for your solution and thanks for participating!:)
 
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