 #1
crememars
 10
 2
 Homework Statement:

Determine the maximum and minimum values for the average speed of an object falling from a height of 2 meters in 0.63 seconds.
Uncertainty of time = +/ 0.05 s
Uncertainty of height = +/ 0.02 m
 Relevant Equations:
 v = ∆y/∆t
Hi! I know this may seem like a silly question but I really just want to make sure I understand this correctly. I've already calculated the minimum and maximum values for time and height:
t min = 0.58 s
t max = 0.68 s
y min = 1.98 m
y max = 2.02 m
To calculate the minimum average speed, would I use the minimum values of time and height ? (and vice versa for max speed)
I thought that would be the process, but the minimum values give a bigger speed, and the max values give me a smaller speed:
v measured = 2.00/0.63 = 3.17 m/s
v min = 1.98/0.58 = 3.41 m/s
v max = 2.02/0.68 = 2.97 m/s
This is really confusing..
t min = 0.58 s
t max = 0.68 s
y min = 1.98 m
y max = 2.02 m
To calculate the minimum average speed, would I use the minimum values of time and height ? (and vice versa for max speed)
I thought that would be the process, but the minimum values give a bigger speed, and the max values give me a smaller speed:
v measured = 2.00/0.63 = 3.17 m/s
v min = 1.98/0.58 = 3.41 m/s
v max = 2.02/0.68 = 2.97 m/s
This is really confusing..