- #1

crememars

- 15

- 2

- Homework Statement
- Determine the maximum and minimum values for the average speed of an object falling from a height of 2 meters in 0.63 seconds.

Uncertainty of time = +/- 0.05 s

Uncertainty of height = +/- 0.02 m

- Relevant Equations
- v = ∆y/∆t

Hi! I know this may seem like a silly question but I really just want to make sure I understand this correctly. I've already calculated the minimum and maximum values for time and height:

t min = 0.58 s

t max = 0.68 s

y min = 1.98 m

y max = 2.02 m

To calculate the minimum average speed, would I use the minimum values of time and height ? (and vice versa for max speed)

I thought that would be the process, but the minimum values give a bigger speed, and the max values give me a smaller speed:

v measured = 2.00/0.63 = 3.17 m/s

v min = 1.98/0.58 = 3.41 m/s

v max = 2.02/0.68 = 2.97 m/s

This is really confusing..

t min = 0.58 s

t max = 0.68 s

y min = 1.98 m

y max = 2.02 m

To calculate the minimum average speed, would I use the minimum values of time and height ? (and vice versa for max speed)

I thought that would be the process, but the minimum values give a bigger speed, and the max values give me a smaller speed:

v measured = 2.00/0.63 = 3.17 m/s

v min = 1.98/0.58 = 3.41 m/s

v max = 2.02/0.68 = 2.97 m/s

This is really confusing..