Evaluating Triple Integral of G: xyz dV

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SUMMARY

The discussion focuses on evaluating the triple integral \(\int\int\int_{G} xyz dV\) over the region \(G\) defined by the boundaries \(x=1\), \(y=x\), \(y=0\), \(z=0\), and \(z=2\). The approach involves first treating two variables as constants and integrating over the remaining variable. Specifically, the integral is evaluated in the triangular region defined by \(0 \leq x \leq 1\) and \(0 \leq y \leq x\), followed by integrating the result with respect to \(z\) from 0 to 2. The final computed value of the integral is \(1/3\).

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Given the triple integral [tex]\int\int\int_{G}[/tex] xyz dV
Where G is the region bounded by x=1, y=x, y=0, z=0, z=2.
How do I evaluate it.
Please help.
 
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First of all, is there any other constraint on x? I'll assume that x>=0.
Do you know how to change triple integrals into single-variable integrals?
The general idea is to first evaluate the integral while pretending that 2 of the variables are constant. Then you use that result to integrate over the other variables.

In this case it might be easiest to first evaluate the integral in the triangle 0<=x<=1 and
0<=y<=x while assuming that z is constant. Then integrate that result with z as a variable from 0 to 2. The triangle can be evaluated in a similar way. In other words:
[tex]I = \int^{2}_{0}(\int^{1}_{0}(\int^{1-x}_{0} xyz dy)dx)dz[/tex]
 
Cheers. I got an answer of 1/3
 

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