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Example involving conditional probability and transitivity

  1. Sep 9, 2013 #1
    I'm just going to post a screenshot of the Example (free online textbook). I'm having a tough time making the leap to the first sum - what allows me to rewrite P(T|A) as the sum of the product of those two conditional probabilities?

    x0YhzYJ.png

    Thanks
     
  2. jcsd
  3. Sep 9, 2013 #2

    Office_Shredder

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    It doesn't have anything to do with the fact that you have a conditional probability to start, it's an application of the more general statement
    [tex] P(X=true) = P(X=true | Y = true)P(Y= true) + P(X = true | Y = false)P(Y = false) [/tex]
     
  4. Sep 9, 2013 #3
    Well I understand the bolded statement. I don't know why it doesn't have anything to do with the fact that I'm dealing with a conditional probability, since it's P( T = tr | A = tr ). In my mind I'm looking for an algebraic substitution or something that I know that allows me to manipulate this into something resembling P(T|A,F). What I don't know is where the P(T|A,F)*P(F|A) comes from or how I could get there.

    For example, why not P(T|F,A)*P(F) and sum over F? Why is it P(F|A)?
     
  5. Sep 10, 2013 #4
    Ok, I found what I was looking for. It's an application of the law of total probability for conditional probabilities:

    8UvY6P4.png
     
  6. Sep 10, 2013 #5

    Stephen Tashi

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    What is the notation "P(T|A,F)" supposed to mean? It isn't consistent with the notation in the image you gave.
     
  7. Sep 10, 2013 #6
    Just an attempt to shorthand what was in the image since I'm on my phone. That post should just be ignored at this point.
     
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