Example of a Lie group that cannot be represented in matrix form?

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I am not sure if this is the right forum to post this question.
The title says it all: are there examples of Lie groups that cannot be represented as matrix groups?

Thanks in advance.
 
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Here (at the beginning) is an example of a local Lie group
https://www.physicsforums.com/insights/journey-manifold-su2mathbbc-part/

However, we have the adjoint representation ##\operatorname{Ad}\, : \,G\longrightarrow \operatorname{GL}(\mathfrak{g})##, and ##\operatorname{Ad}(G)## is a Lie subgroup of ##\operatorname{GL}(\mathfrak{g})##. If it is a monomorphism, we automatically get ##\operatorname{G}\cong \operatorname{Ad}(G)## and have a matrix group.
 
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fresh_42 said:
Here (at the beginning) is an example of a local Lie group
https://www.physicsforums.com/insights/journey-manifold-su2mathbbc-part/

However, we have the adjoint representation ##\operatorname{Ad}\, : \,G\longrightarrow \operatorname{GL}(\mathfrak{g})##, and ##\operatorname{Ad}(G)## is a Lie subgroup of ##\operatorname{GL}(\mathfrak{g})##. If it is a monomorphism, we automatically get ##\operatorname{G}\cong \operatorname{Ad}(G)## and have a matrix group.
Your notation for the unitary groups is unconventional.
 
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martinbn said:
##\widetilde{SL}_2(\mathbb R)##
Thank you. Can you tell me how it is defined, or under what name I can look up information about that group?
 
fresh_42 said:
I guess we want to have a faithful representation to call a group a matrix group.
How about the Cayley representation then, as a group of permutations?
 
fresh_42 said:
Are we still talking about Lie groups?
Cant every group be described as a permutation group? Unless you want to preserve any other than algebraic properties, it seems it would work, though I don't see how to do it with Lie groups.
 
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WWGD said:
Cant every group be described as a permutation group? Unless you want to preserve any other than algebraic properties, it seems it would work, though I don't see how to do it with Lie groups.
If the group is not finite, these permutations are not going to be matrices.
 
martinbn said:
##\widetilde{SL}_2(\mathbb R)##

martinbn said:
Metaplectic

These groups are different. The metaplectic group ##Mp(2)## is not simply connected because it is a double cover of ##Sp(2)=SL_2(\mathbb{R}),## which has fundamental group of ##\mathbb{Z}##.
 
Infrared said:
These groups are different. The metaplectic group ##Mp(2)## is not simply connected because it is a double cover of ##Sp(2)=SL_2(\mathbb{R}),## which has fundamental group of ##\mathbb{Z}##.
Yes, but that was clear from the link.
 
Infrared said:
These groups are different. The metaplectic group ##Mp(2)## is not simply connected because it is a double cover of ##Sp(2)=SL_2(\mathbb{R}),## which has fundamental group of ##\mathbb{Z}##.

The tilde on top of the group "name" exactly universal cover of that group means. So the two groups are not different.
 
dextercioby said:
The tilde on top of the group "name" exactly universal cover of that group means. So the two groups are not different.
The universal cover of a space is simply connected. The metaplectic group is not simply connected. So they are different.
 
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