Example on Z-modules .... Dummit & Foote, Page 339 ....

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The discussion focuses on Dummit and Foote's "Abstract Algebra" (Third Edition), specifically Chapter 10 on Module Theory, and an example regarding Z-modules in Section 10.1. The example illustrates how the module axioms confirm that the only action of the integers (ℤ) on a set A, making it a unital ℤ-module, is through the defined scalar multiplication. The reasoning provided by Peter shows that for any positive integer n, the action is derived from the property of ℤ, leading to the conclusion that the defined action is unique.

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I am reading Dummit and Foote's book: "Abstract Algebra" (Third Edition) ...

I am currently studying Chapter 10: Introduction to Module Theory ... ...

I need some help with an aspect of Dummit and Foote's example on Z-modules in Section 10.1 Basic Definitions and Examples ... ... Dummit and Foote's example on Z-modules reads as follows:
https://www.physicsforums.com/attachments/8001In the above example we read the following:

" ... ... This definition of an action on the integers on $$A$$ makes $$A$$ into a $$\mathbb{Z}$$-module, and the module axioms show that this is the only possible action of $$\mathbb{Z}$$ on $$A$$ making it a (unital) $$\mathbb{Z}$$-module ... ... "Can someone please explain how/why the module axioms demonstrate that this is the only possible action of $$\mathbb{Z}$$ on $$A$$ making it a (unital) $$\mathbb{Z}$$-module ... ... ? How do we know it is the only possible such action ... ... ?Hope someone can help ...

Peter
 
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If $n>0$ then $n = 1+1+\ldots + 1$ (property of $\Bbb{Z}$). Therefore $$na = (1+1+\ldots + 1)a = 1a + 1a + \ldots + 1a = a+a+\ldots + a,$$ using the module axioms. So that is the only possible value for $na$.The cases $n=0$ and $n<0$ work in a similar way, starting from the facts that $0 = 1 + (-1)$ and $-n = (-1)n$.
 

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