MHB Example on Z-modules .... Dummit & Foote, Page 339 ....

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The discussion focuses on understanding the unique action of the integers on a set A to form a Z-module, as presented in Dummit and Foote's "Abstract Algebra." The key point is that the module axioms dictate how scalar multiplication operates, specifically showing that for any positive integer n, the expression na can only be represented as a sum of a repeated element a. This reasoning extends to cases for n=0 and negative integers, confirming that the defined action is consistent and exhaustive. Thus, the axioms imply that the defined action is the only viable method for Z to act on A, establishing A as a unital Z-module. The clarity of these axioms is crucial for understanding module theory in this context.
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I am reading Dummit and Foote's book: "Abstract Algebra" (Third Edition) ...

I am currently studying Chapter 10: Introduction to Module Theory ... ...

I need some help with an aspect of Dummit and Foote's example on Z-modules in Section 10.1 Basic Definitions and Examples ... ... Dummit and Foote's example on Z-modules reads as follows:
https://www.physicsforums.com/attachments/8001In the above example we read the following:

" ... ... This definition of an action on the integers on $$A$$ makes $$A$$ into a $$\mathbb{Z}$$-module, and the module axioms show that this is the only possible action of $$\mathbb{Z}$$ on $$A$$ making it a (unital) $$\mathbb{Z}$$-module ... ... "Can someone please explain how/why the module axioms demonstrate that this is the only possible action of $$\mathbb{Z}$$ on $$A$$ making it a (unital) $$\mathbb{Z}$$-module ... ... ? How do we know it is the only possible such action ... ... ?Hope someone can help ...

Peter
 
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If $n>0$ then $n = 1+1+\ldots + 1$ (property of $\Bbb{Z}$). Therefore $$na = (1+1+\ldots + 1)a = 1a + 1a + \ldots + 1a = a+a+\ldots + a,$$ using the module axioms. So that is the only possible value for $na$.The cases $n=0$ and $n<0$ work in a similar way, starting from the facts that $0 = 1 + (-1)$ and $-n = (-1)n$.
 
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