Examples where it's Riemann integrable but no derivative exists at pts

[Nusc]

What is an example where it's Riemann integrable int(f(t),t,a,x) but no derivative exists at certain pts?

 

[HallsofIvy]

The function f(x)= 0 if x\le 0, 1 if x> 0 is integrable but has no derivative at x= 0. More generally, if f(x) has finite "jump" discontinuities at some points, it is still Riemann integrable but is not differentiable at those points.

 

[0xDEADBEEF]

or f(x)=\left| x\right|

 

[HallsofIvy]

Those two examples also have the property that while F(x)= \int f(t)dt is defined, F(x) itself has no dervative at x= 0.

 

[mathwonk]

there are functions which are continuous everywhere hence integrable, but differentiable nowhere. perhaps the famous dirichlet function which equals zero at irrationals and 1/q at p/q is even differentiable nowhere. since it is continuous a.e. it is integrable.

 

[Gaenn]

V_{3}[\tex]

 

[arildno]

An example of a continuous (and hence integrable) function that is nowhere differentiable is the Weierstrass function:
F(x)=\sum_{n=0}^{\infty}\frac{\sin((n!)^{2}x)}{n!}

 

[Doodle Bob]

Those two examples also have the property that while F(x)= \int f(t)dt is defined, F(x) itself has no dervative at x= 0.

I'm not sure about this. Isn't F(x)= \int_0^x |t|dt differentiable at 0? It is the piecewise function given by F(x)=x^2 for x>0 and F(x)=-x^2 for x>0 and F(0)=0.

 

[HallsofIvy]

Yes, you are right. That was an error on my part.