Exergonic Reactions: Polar Molecule Stability?

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SUMMARY

Exergonic reactions, such as the combustion of methane, often produce polar molecules like water (H2O) and carbon dioxide (CO2). While H2O is polar, CO2 is nonpolar due to the symmetrical arrangement of its oxygen atoms, which balances the electron pull. The stability of polar molecules is attributed to their ability to lower energy states, making them favorable products in exergonic processes. Understanding the stability of these products is crucial for predicting reaction outcomes.

PREREQUISITES
  • Basic knowledge of exergonic reactions
  • Understanding of molecular polarity
  • Familiarity with combustion processes
  • Concept of energy states in chemical reactions
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  • Research the principles of molecular polarity and its impact on stability
  • Study the thermodynamics of exergonic reactions
  • Explore methods for predicting reaction products based on stability
  • Learn about the role of electron distribution in molecular interactions
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Chemistry students, researchers in thermodynamics, and anyone interested in the stability of molecular products in chemical reactions.

nobahar
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Hello!
Quick question, but it's really bugging me!
Exergonic reactions often yield polar molecules as the products (e.g. combustion of methane). Are these polar molecules 'favourable' because the electrons are spending more time in a lower energy region; or is this wrong, and there's a different reason why polar molecules are more stable?
All responses appreciated.
 
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Give us an example of the polar molecules you are referring to regarding the combustion of methane. CO2 and H2O? One is polar and one isn't...
 
Ohhhh, CO2 isn't polar because the 'pull' of the oxygen atoms is 'balanced'. So I'm guessing polar molecules are not stable more generally? Why would they be, I suppose...
In that case, is there a method of determining the most likely products of a reaction, given that they attempt to form the most stable products?
Thanks for the reply, and any further ones. :smile:
 

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