Expanding Logarithms with Radicals

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Homework Help Overview

The discussion revolves around the expansion of logarithmic expressions involving radicals, specifically the expression log2√x. Participants are exploring how to manipulate this expression using properties of logarithms and fractional exponents.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to express log2√x in terms of log2x, considering fractional exponents and questioning the validity of their approaches. There is discussion about whether the expression can be simplified to forms like 1/2(log2x) or (log2x)/2(log2x).

Discussion Status

The discussion is active, with participants sharing their thoughts and questioning their reasoning. Some have suggested writing √x with a fractional exponent, while others are exploring the implications of this approach. There is no explicit consensus yet on the correct form of the expression.

Contextual Notes

Participants note that their textbook examples do not include radicals, which may be influencing their understanding and approach to the problem.

Deagonx
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Homework Statement


log2√x

Homework Equations


The Attempt at a Solution



I thought that it might be something like log2x - log2x but that's not right. The book examples don't have any radicals.
 
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Deagonx said:

Homework Statement


log2√x


Homework Equations





The Attempt at a Solution



I thought that it might be something like log2x - log2x but that's not right. The book examples don't have any radicals.
Write √x with a fractional exponent.
 
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)
 
Deagonx said:
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)

##log(a^b) = b \cdot log(a)##
 
Deagonx said:
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)
Why would you even consider that [itex]log_2(\sqrt{x})= 1/2[/itex] for all x?
 

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