Expansion coefficients of a wave packet

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Homework Help Overview

The discussion revolves around determining the expansion coefficients of a wave packet represented by the function \(\Psi (x) = \sqrt{\frac{2}{L}} \sin \frac{\pi x}{L}\) in the context of a particle in a periodic box of size \(L\). Participants are exploring the relationship between the wave packet and the basis functions of the system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of inner products to find the coefficients \(a_{n}(t)\) and question how to apply this to the specific wavefunction given that it lacks an explicit \(n\) dependence. There is also a consideration of the basis functions for the potential, with some participants suggesting the use of exponential forms and others expressing confusion about the implications of time dependence in the coefficients.

Discussion Status

The discussion is ongoing, with participants providing insights into the mathematical framework and questioning the appropriateness of their methods. Some guidance has been offered regarding the expansion of sine functions into exponentials, but there remains uncertainty about the correct approach and interpretation of the problem.

Contextual Notes

Participants note the complexity introduced by the expansion and express uncertainty regarding the question's requirements, particularly concerning the time dependence of the wavefunctions involved.

rwooduk
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Homework Statement


What are the expansion coefficients of a wavepacket \Psi (x) = \sqrt{\frac{2}{L}}sin \frac{\pi x}{L} in the basis Ψn(x) of a particle in a periodic box of size L?

Homework Equations


\Psi (r,t) = {\sum_{n}^{}} a_{n}(t) \Psi _{n}(r)

The Attempt at a Solution


\left \langle \Psi _{m}| \Psi \right \rangle= {\sum_{n}^{}} a_{n}(t)\left \langle \Psi _{m}| \Psi_{n} \right \rangle

all zero except for m=n therefore

a_{n}(t)=\left \langle \Psi _{n}| \Psi \right \rangle

so I have a term for the coefficients but how do I apply it to the specific wavefunction? espcially as it has no n in it.

Any help as always very much appreciated. Thanks.
 
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What are the basis functions for your potential?
 
Orodruin said:
What are the basis functions for your potential?

hmm do you mean the basis wavefunctions? if it's a periodic box then

\Psi _{n}=\sqrt{\frac{1}{L}} exp(\frac{i2\pi nx }{L})

so i substitute this into the above an(t) equation?

thanks for the reply!

edit i expanded the exponential in terms of cos and sin but it gets a bit complicated, also not sure what to do with the Σan that's on the right hand side.
 
Last edited:
It will be more fruitful to expand the sine in terms of exponentials ...
 
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Apologies for the late reply. I'm getting really lost with this one, I'm really not sure my method is correct as there is no time dependence in either wavefunction, so why am I using an(t).

If I use:
a_{n}(t)=\left \langle \Psi _{n}| \Psi \right \rangle
with

\Psi _{n}=\sqrt{\frac{1}{L}} exp(\frac{i2\pi nx }{L})
\Psi (x) = \sqrt{\frac{2}{L}}sin \frac{\pi x}{L}

but then expand

\Psi (x) = \sqrt{\frac{2}{L}}sin \frac{\pi x}{L}

\Psi (x) = \sqrt{\frac{2}{L}}sin \frac{\pi x}{L} = \sqrt{\frac{2}{L}}\frac{1}{2i}(exp\frac{in\pi}{L}- exp \frac{-in\pi}{L})

so I get

a_{n}(t) = \int_{0}^{L} \sqrt{\frac{1}{L}} exp(\frac{i2\pi nx }{L})\sqrt{\frac{2}{L}}\frac{1}{2i}(exp\frac{in\pi}{L}- exp \frac{-in\pi}{L}) dx

this can't be correct?

any further help on this would be appreciated, I still don't really understand what the question is asking to be honest.
 

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