- #1

Nezva

- 46

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In the case of [tex]\Psi=c[/tex]

_{1}[tex]\Psi[/tex]

_{1}[tex] + c[/tex]

_{2}[tex]\Psi[/tex]

_{2}[tex] + ... + c[/tex]

_{n}[tex]\Psi[/tex]

_{n}

And the

**operator**A(hat) => A(hat)[tex]\Psi[/tex]

_{1}= a

_{1}[tex]\Psi[/tex]

_{1}; A(hat)[tex]\Psi[/tex]

_{2}= a

_{2}[tex]\Psi[/tex]

_{2}; A(hat)[tex]\Psi[/tex]

_{n}= a

_{n}[tex]\Psi[/tex]

_{n}

Calculate: [tex]\left\langle\Psi\left|A(hat)\right|\right\Psi\rangle[/tex]