Explain Force of Thrust Equation: 6N/3.48s

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physicnoob101
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Please Explain this?!

hey, ok so i was going tthrough my textbook and following some examples hwne i cam up to this:

Force of Thrust = Ft/ delta T

= 6N / 3.48s

=1.7 N

but it doesn't say what the equation means. can someone please help me and explain what is happeing.
 
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A little more information regarding the problem would be helpful. However, how can one divide Newtons by time and wind up with Newtons?
 


Have you covered momentum yet? I don't remember how to calculate force of thrust without using momentum, so I hope this is helpful to you.

The equation for Force of Thrust I know, is
F(thrust) = ((m * V)2 - (m * V)1) / (t2 - t1)

This can also be written as
F(thrust) = Δp / Δt
Force of thrust = change in momentum / change in time

Which would give you
N = N*s/s
meaning your seconds would cancel to give the correct units.
 


the doth prevous questins are pretty good. But i don't understand why did u posted a quastion that is already answered.. If you don't understand it just read the 3-4 prevous pages of your book! That is not so difficult (sorry about my english and wrong words sometimes,,, ist because I am writing from my mobile)