Explain why Mo–95 & La–139 are more stable than U–235

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SUMMARY

Mo–95 and La–139 exhibit greater stability than U–235 primarily due to their binding energy characteristics as described by the Semiempirical Mass formula. This formula accounts for various factors affecting nuclear stability, including volume, surface tension, Coulomb repulsion among protons, symmetry, and neutron-proton pairing. The significant Coulomb repulsion in heavier nuclei like U–235 contributes to its instability, while Mo–95 and La–139 benefit from a more favorable proton-neutron ratio and lower Coulomb repulsion. Understanding these concepts is essential for analyzing nuclear stability.

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  • Semiempirical Mass formula
  • Nuclear binding energy concepts
  • Coulomb repulsion in nuclei
  • Proton-neutron ratio analysis
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Bolter
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Homework Statement
See question below
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Hey everyone!

So I have attempted this Q which is shown below

Screenshot 2020-04-20 at 20.24.38.png

I had a go at all the parts and I think they are right
but I'm not so sure on what answer to give for c)iii, I mentioned about the ratio of protons to neutrons but I'm not sure if that is necessary over here?

IMG_4646.JPG

IMG_4647.jpg


Any help would be grateful! Thanks
 
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Hi,

The Semiempirical Mass formula gives an idea of binding energy in nuclei. It treats the nuclei as fluid, so a number of terms are introduced: volume, surface tension, coulomb repulsion among protons, symmetry, and pairing neutron-proton.
https://en.wikipedia.org/wiki/Semi-empirical_mass_formula

There are a number of factors that weaken heavy nuclei, the most important is the Coulomb repulsion among protons. In this graph, each component of the mass formula is displayed, so you can see which one changes the most from A~240, to A~100.
https://www.slideserve.com/sasha/the-semi-empirical-mass-formula

I hope it helps.

Regards,
ORF
 
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