Hi everyone ^^! I hope you had a great holiday season. I have a homework problem that I'm a little confused on. I will provide my answers/work as usual, and would like it if someone could check my work, or tell me if an explanation is wrong/needs more information. My teacher would like us to be very specific on these so I'm not sure if my explainations are well-explained enough. Though, I would like to say that I've been doing very well on my tests lately because I apply what I learn from everyone here on my tests and am finally starting to do really well ^^. Thanks. ---------------------------------------------------------------------- Solve the following problem. (Hint: Use the Ideal Gas Laws and the first law of thermodynamics) Be specific and support your responses. Diagram: http://img.photobucket.com/albums/v696/talimtails/PP18.jpg Four samples of ideal gas are each initially at pressure Po, a volume Vl, and a temperature To, as show on the diagram above. The samples are taken in separate experiments from this initial state to the final states I, II, III, and IV along the processes shown on the diagram. a. One of the processes is isothermal. Identify this one and explain. Process II is isothermal. The temperature remains constant and pressure varies directly with volume. b. One of the processes is adiabatic. Identify this one and explain. Process III is adiabatic because no heat is transferred during the process. Furthermore, adiabatic processes have a steeper inclination than isotherms because they lose more pressure during expansion. c. In which process or processes does gas do work? Explain. W = P∆V. In process IV volume remains constant and therefore there is no work. Thus, in processes I, II, and III work is done because there is a change in volume. d. In which process or processes is heat removed from the gas? Explain. ∆U = Q – W. In processes II, III, and IV heat is removed from the gas because there is a decrease from the initial temperature as shown by the decreasing slopes of the lines. e. In which process or processes does the root-mean-square speed of the gas molecules increase? Explain. Vrms = sqrt (3RT/Mm) If the temperature decreases, the speed of the gas particles decreases as well. Therefore, because none of the processes experience an increase in temperature, there are no processes in which the root-mean-square speed of the gas molecules increase.