Explaination - Cent. Acceleration and Tangential Acceleration,

[grandprix]

Homework Statement

Two formula on racing cars are negotiating a circular turn, and they have the same cent. acceleration. However, the path of car A has a radius of 48 m, while that of car B is 36 m. Determine the ration of angular sped of car A to the angular speed of car B.

Homework Equations

v² = \omega² + r²

acent = v²/r

The Attempt at a Solution

so somehow i got the right answer by taking the square root of (3/4). Basically i am wondering if someone could help me go through the algebra to get the final result.

Thanks

 

[grandprix]

actually i know how to do the algbra what i meant to ask was why is it th squareroot of (3/4) and not (4/3)

 

[rock.freak667]

F=\omega^2 r


F_A=\omega_A^2 r_A

F_B=\omega_B^2 r_B


r_A=48
r_B=36


You want to get w_A/w_B.

Since F_A=F_B => F_A/F_B=1

Does this help showing how to get the answer?

 

[grandprix]

yes! :) thanks very much!