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Explaination - Cent. Acceleration and Tangential Acceleration,

  1. Jun 7, 2009 #1
    1. The problem statement, all variables and given/known data
    Two formula on racing cars are negotiating a circular turn, and they have the same cent. acceleration. However, the path of car A has a radius of 48 m, while that of car B is 36 m. Determine the ration of angular sped of car A to the angular speed of car B.
    2. Relevant equations
    v2 = [tex]\omega[/tex]2 + r2

    acent = v2/r
    3. The attempt at a solution
    so somehow i got the right answer by taking the square root of (3/4). Basically i am wondering if someone could help me go through the algebra to get the final result.

    Thanks
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 7, 2009 #2
    actually i know how to do the algbra what i meant to ask was why is it th squareroot of (3/4) and not (4/3)
     
  4. Jun 7, 2009 #3

    rock.freak667

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    Homework Helper

    [tex]F=\omega^2 r[/tex]


    [tex]F_A=\omega_A^2 r_A[/tex]

    [tex]F_B=\omega_B^2 r_B[/tex]


    rA=48
    rB=36


    You want to get wA/wB.

    Since FA=FB => FA/FB=1

    Does this help showing how to get the answer?
     
  5. Jun 7, 2009 #4
    yes! :) thanks very much!!
     
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