Explaining the Joint Distribution of T1,T2,...,Tn given N(t)=n

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Discussion Overview

The discussion revolves around the joint distribution of event times T1, T2, ..., Tn in a Poisson process, given that N(t)=n. Participants are exploring the implications of this condition on the distribution and the interpretation of event occurrences within specified intervals.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant explains that the event {T1≤t1, T2≤t2,..., Tn≤tn, and N(t)=n} occurs if exactly one event happens in each of the intervals [0,t1], (t1,t2],..., (tn-1,tn], and no events occur in (tn,t).
  • Another participant questions the interpretation of 'exactly one' event, suggesting that T2 could be less than t1, which might imply multiple events in [0,t1], thus challenging the initial explanation.
  • Some participants propose that the condition of having exactly one event per interval is a definitional choice that aids in deriving the joint distribution function.
  • There is a repeated inquiry about whether N(t)=n can still hold if T2 is less than t1, with differing opinions on the implications of this scenario.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the implications of the condition N(t)=n and whether it allows for multiple events in the intervals defined. There is no consensus on the interpretation of the 'exactly one' condition in relation to the event times.

Contextual Notes

Participants highlight potential confusion stemming from the definitions used in the problem, particularly regarding the intervals and the implications of event occurrences within them. The discussion remains focused on clarifying these definitions without resolving the underlying questions.

kingwinner
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Let {N(t): t≥0} be a Poisson process of rate λ.
We are given that for a fixed t, N(t)=n.
Let Ti be the time of the ith event, i=1,2,...,n.

Then the event {T1≤t1, T2≤t2,...,Tn≤tn, and N(t)=n} occurs if and only if exactly one event occurs in each of the intervals [0,t1], (t1,t2],..., (tn-1,tn], and no events occur in (tn,t].
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I don't understand the 'exactly one' part.
For example, T2≤t2 just says that T2 is less than or equal to t2, and T2 can very possibly be less than t1 as well, right? (since it did NOT say that T2 MUST be larger than t1) In this case, we would then have more than one event occurring in [0,t1]. Why is this not allowed? I don't get it...

Can someone please explain? I would really appreciate it!
 
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Would N(t)=n be satisfied if T2 < t1?
 
It seems to be a definitional choice that serves some purpose in the rest of the problem.
 
EnumaElish said:
Would N(t)=n be satisfied if T2 < t1?

I think so! We can possibly have all n points in the interval [0,t1].
 
The book is trying to prove that the joint density function of T1,T2,...,Tn given that N(t)=n is given by (n!)/(t^n), 0<t1<t2<...<t_n<t

They are first trying to find the joint distribution function for 0<t1<t2<...<t_n<t.
i.e. P(T1≤t1,...Tn≤tn |N(t)=n)
and they commented that "the event {T1≤t1, T2≤t2,...,Tn≤tn, and N(t)=n} occurs if and only if exactly one event occurs in each of the intervals [0,t1], (t1,t2],..., (tn-1,tn], and no events occur in (tn,t". This is where I got totally confused...

Can someone please help?
 

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