Explaining the Relationship between Factors and Multiples | ALC, BLC, and (AB)LC

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Homework Help Overview

The discussion revolves around the relationship between factors and multiples, specifically exploring the statements involving alc, blc, and (ab)lc. Participants are attempting to clarify the validity of these relationships in the context of number theory.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the reasoning behind why a product of factors is also a factor of a multiple. There are attempts to identify where misunderstandings may arise, particularly in the context of specific examples.

Discussion Status

The discussion is ongoing, with some participants expressing confusion about previous posts and others attempting to clarify misconceptions. There is a recognition of differing interpretations of the relationships being discussed.

Contextual Notes

Some participants reference previous discussions and express uncertainty about the validity of the statements being analyzed. There is mention of specific examples that challenge the initial assumptions.

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Homework Statement


alc, blc, then (ab)lc
I'm trying to explain why this is true


Homework Equations





The Attempt at a Solution


a is a factor of c an b is a factor of c.
ab is a factor of c is true because a will still be a factor of c and b will still be a factor of c.
 
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I don't know where I'm going wrong
 
Other people do know where you are going wrong. And they told you why the first time you posted it. Why don't you read the first post? Stop it.
 
Ok, I think i figured it out. It's not true because we can have 6l6 and 2l6, but not 12l6.
 
Dick said:
Other people do know where you are going wrong. And they told you why the first time you posted it. Why don't you read the first post? Stop it.

Sorry, but I never posted this before.
 

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