Exponential laws logrithm function.

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SUMMARY

The discussion focuses on solving the equation y = -(((e^x)/(e^-x))/2) + ((e^x)/(e^(-3x))) for y = 5. The user simplifies the equation to y = -1/2(e^(2x)) + (e^(4x)) and correctly applies logarithmic properties to isolate x. The final solution derived is x = ln|5|/3, confirming the validity of the steps taken. The user also notes the distinction that ln(a+b) ≠ ln(a) + ln(b), emphasizing the importance of logarithmic rules in the solution process.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Familiarity with logarithmic identities and rules
  • Basic algebraic manipulation skills
  • Knowledge of substitution methods in equations
NEXT STEPS
  • Study the properties of logarithms, specifically ln(a+b) vs. ln(a) + ln(b)
  • Explore substitution techniques in solving exponential equations
  • Learn about the implications of using e as a base in exponential functions
  • Investigate advanced topics in calculus related to exponential growth and decay
USEFUL FOR

Mathematics students, educators, and anyone interested in solving exponential equations and understanding logarithmic functions.

italian1013
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find x for y=5

y = -(((e^x)/(e^-x))/2) + ((e^x)/(e^(-3x))

all i did was a^m / a^n = a^m-n

i get here y = -1/2(e^(2x)) + (e^(4x))
after this i get iffy and want to make sure i can do what i did.

5 = -1/2(e^(2x)) + (e^(4x))
ln|5|= -1/2(ln(e^2x)) + ln(e^4x)
ln|5|= -1/2(2x) + 4x
ln|5|= -x + 4x
ln|5|= 3x

x = ln|5|/3

is this right?
 
Physics news on Phys.org
[tex]ln(a+b)\neq ln(a)+ln(b)[/tex]

Substitute [tex]u=e^{2x}[/tex]
 

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