Expressing answers answers for numbers and unites.

  • Thread starter Thread starter Sun44
  • Start date Start date
  • Tags Tags
    Numbers
Click For Summary
SUMMARY

The discussion focuses on calculating the total current value of gold mined historically and converting the density of gold from grams per cubic centimeter to kilograms per cubic meter. The price of gold is stated as $27 per gram, leading to a total valuation of approximately $4.59 trillion for 170,000 tonnes of gold. The density conversion requires applying the factor label method to transition from g/cm³ to kg/m³, emphasizing the need to understand unit conversions in physics and mathematics.

PREREQUISITES
  • Understanding of unit conversion techniques, specifically from grams to kilograms and cubic centimeters to cubic meters.
  • Familiarity with scientific notation and significant figures.
  • Basic knowledge of gold pricing and historical mining data.
  • Proficiency in applying the factor label method for dimensional analysis.
NEXT STEPS
  • Research the factor label method for unit conversions in depth.
  • Learn about the historical context and economic implications of gold mining.
  • Study scientific notation and its applications in calculations.
  • Explore density calculations and conversions in various materials.
USEFUL FOR

Students in physics or chemistry, educators teaching unit conversions, and anyone interested in the economic valuation of precious metals.

Sun44
Messages
4
Reaction score
0

Homework Statement



""""
a) The price of gold, according to << Link removed by Moderator >>is currently $27 per gram. It is
estimated that over the course of history about 170,000 tonnes of gold has been mined,
what would the current price of all this gold be?
b) The density of gold is 19.3 g cm^-3. Express it in units of kgm^-3. """



Homework Equations



Not sure

The Attempt at a Solution



a) 4.59 x 10^12 (3 SF)
 
Last edited by a moderator:
Physics news on Phys.org
Sun44 said:

Homework Statement



""""
a) The price of gold, according to << Link removed by Moderator >>is currently $27 per gram. It is
estimated that over the course of history about 170,000 tonnes of gold has been mined,
what would the current price of all this gold be?
b) The density of gold is 19.3 g cm^-3. Express it in units of kgm^-3. """



Homework Equations



Not sure

The Attempt at a Solution



a) 4.59 x 10^12 (3 SF)
Use the factor label method.

[tex]\frac{19.3 \ g}{cm^3} \cdot \frac{\text{ ? } kg}{\text{ ? } g} \cdot \frac{\text{ ? }}{\text{ ? }} = \text{The Answer}[/tex]

You'll have to figure out what goes in place of all the "?". That is, how do you convert between g and kg? Also, how do you get the cm3 to become m3?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
27K
Replies
12
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K