Expression sin^n(x)/(sin^n(x)+cos^n(x))

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SUMMARY

The expression sin^n(x)/(sin^n(x)+cos^n(x)) simplifies to 1/(cot^n(x)+1) through algebraic manipulation. By dividing both the numerator and denominator by sin^n(x), the expression transforms into 1/[(sin^n(x)+cos^n(x))/sin^n(x)]. This simplification highlights the relationship between sine and cotangent functions in trigonometric identities.

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Vali
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Hi!
I have sin^n(x)/(sin^n(x)+cos^n(x))
The expression is the same with 1/(ctg^n(x)+1) and I have no idea how to get to this answer.
Can you help me?
 
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If you divide the numerator and denominator by \(\sin^n(x)\) what do you get?
 
1/[(sin^n(x)+cos^n(x))/sin^n(x)]
edit:
I get it.Thanks a lot! :)
 

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