External Fields and Negative Energy Transitions In Dirac Particle

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Homework Help Overview

The problem involves a relativistic spin-1/2 particle initially at rest and examines the effects of applying an electric field at time t=0. The goal is to explore the probability of the particle transitioning to a negative energy state, assuming these states are initially empty.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the implications of the particle remaining at rest versus transitioning to a negative energy state. There is uncertainty about the application of first-order perturbation theory and the nature of the final state of the particle, particularly regarding whether it would be an antiparticle and its energy state.

Discussion Status

Some participants have offered guidance on using Dirac matrices to express the perturbed Hamiltonian in terms of positive and negative energy components. However, multiple interpretations of the problem's conditions are being explored, particularly regarding the particle's state after the application of the electric field.

Contextual Notes

There is a noted complexity regarding the relativistic nature of the particle and the assumptions about its initial and final states. The original poster's clarification of the problem's requirements has prompted further discussion on the implications of the external vector potential and its effects on the particle's energy states.

javiergra24
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Homework Statement



Suppose a relativistic particle with spin 1/2 at rest. Show that if we apply an electrical field at t=0 there's a probability fot t>0 of finding the particle in a negative energy state if such negative energy states are assumed to be originally empty.

Homework Equations



Dirac equation at rest:
<br /> (\boldsymbol{\hat{\beta}} mc^2) \psi (\mathbf{x},t) = i \hbar \frac{\partial\psi(\mathbf{x},t) }{\partial t}<br />
Spinor solutions with positive energy for t<0
<br /> $\Psi_{+}=\begin{pmatrix}<br /> \psi^{(1)}\\ \psi^{(2)}<br /> \end{pmatrix}={1\over\sqrt{V}}\begin{pmatrix}<br /> 1\\ 1\\ 0\\ 0<br /> \end{pmatrix}e^{-imc^2t/\hbar}$\\<br /> <br />
Applied electrical field and consecuent magnetic potential
<br /> $\mathbf{E}=E_0 \cos(\omega t)\mathbf{u}_{x} \qquad \mathbf{A}=-\frac{E_0}{\omega} \sin(\omega t)\mathbf{u}_{x}$<br />

The Attempt at a Solution



I'm not sure how to solve this problem. Is it supposed that the particle at t>0 remains at rest? Or it has a negative energy E'?. First order perturbation theory must be used, but how about the final state of the particle?

Perturbed Hamiltonian should be
<br /> $\displaystyle H&#039;(t)=q c \boldsymbol{\hat{\alpha}} \mathbf{A}=q c\hat{\alpha}_{x}A_{x}$<br />
Is it correct?

Thank you
 
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The perturbed Hamiltonian acts on the spinor wavefunction. You'll need to use the Dirac matrices to write things in terms of the positive and negative energy components.
 
Last edited:
But the final state would be an antiparticle at rest? Or with some energy?
 
javiergra24 said:
But the final state would be an antiparticle at rest? Or with some energy?

Oh I missed that the spinor is relativistic. A relativistic particle is not at rest, so neither the initial or final state are at rest.
 
Umm a relativistic particle can be at rest, with E=mc^2. The exact problem is:

"Consider a positive energy spin-1/2 particle at rest. Suppose that at t=0 we apply an external
(classical) vector potential (see mi first post)
which corresponds to an electric field of the form
Show that for there exists a finite probability of finding the particle in a negative energy state if
such negative energy states are assumed to be originally empty. In particular, work out quantitatively
the two cases: w>>mc^2 and w=mc^2 and and comment."
 

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