F = ma doesn't work when aproaching c

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As an object approaches the speed of light (c), its relativistic mass increases, which makes it impossible for the object to reach c due to the infinite force required for further acceleration. The relationship F = ma does not completely break down; rather, it is modified to account for relativistic effects, where mass can be expressed as m = γm₀, with γ being the Lorentz factor. At low velocities, γ is close to 1, making F = ma approximately valid. The increase in energy and mass with velocity is explained by the equations E = mc² and kinetic energy formulas. Understanding these concepts is crucial for grasping the limitations of classical physics in relativistic contexts.
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Hello all,

Im only a student, taking physics in college in september, However I have read up on the level of physics I will be studying. One thing that I couldn't get my head round, Why when an object aproaches c does its mass increase? Am I right in saying this also makes it impossible from the object to reach c? Also why does this cancel out f = ma?

Sorry if this seems like a stupid question, but it just sparked an interest in my mind and I couldn't find an explanation that actually fully explained it to me. Thanks all.
 
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There are basically two ways of describing this in relativity.

The more old-fashioned way is to write F=ma, and say that m=\gamma m_o, where m_o is the mass the object has when it's at rest.

More recently (roughly within the last 50 years), it's been more common to write F=m\gamma a, and treat m as a constant.

So depending on which description you prefer, you can either say that mass increases or it doesn't increase, but either way the prediction is the same.

It doesn't cancel out F=ma completely. At velocities that are small compared to the speed of light, \gamma is very close to 1, so F=ma is approximately right. That's why people believed F=ma was exact for hundreds of years.

Yes, this is one way of seeing that an object can't reach c. As its velocity gets close to c, \gamma approaches infinity, so the force required in order to maintain the same acceleration also approaches infinity.

For an explanation of why this happens: http://www.lightandmatter.com/html_books/6mr/ch01/ch01.html#Section1.3
 
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Jacob_hull said:
Hello all,

Im only a student, taking physics in college in september, However I have read up on the level of physics I will be studying. One thing that I couldn't get my head round, Why when an object aproaches c does its mass increase? Am I right in saying this also makes it impossible from the object to reach c? Also why does this cancel out f = ma?

Sorry if this seems like a stupid question, but it just sparked an interest in my mind and I couldn't find an explanation that actually fully explained it to me. Thanks all.

The mass increases because m = e/c^2 and E = 1/2mv^2

This means that if your velocity increases your energy increases your mass increases.

You are correct, a massive object can't reach the speed c.

Also f=ma does not work at speed c because the force would be infinite along with the mass which essentially states 1=1 since "a" now equals next to 0. Perhaps it works it is just not very interesting.
 
Thanks for the reply, this sort of stuff doesn't get explained to you in Secondary school it was basically f=ma end of. But I understand now so thanks a lot :)
 
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