F(x) = x2-7 and g(x) = x- 3, find (f º g )(x) [2]

  • Context: MHB 
  • Thread starter Thread starter trevor
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Discussion Overview

The discussion revolves around finding the compositions of two functions, f(x) = x² - 7 and g(x) = x - 3. Participants are exploring the calculations for (f º g)(x), (g º f)(x), and the inverses of the functions.

Discussion Character

  • Homework-related

Main Points Raised

  • Some participants clarify that (f º g)(x) means f(g(x)), indicating that g(x) should be substituted into f(x).
  • One participant expresses uncertainty about how to proceed with the problem.
  • Another participant asks what the original poster has attempted so far, indicating a collaborative approach.

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants expressing different levels of understanding and no consensus on the solutions to the problems posed.

Contextual Notes

There are indications of missing steps in the calculations and assumptions about the functions that have not been explicitly stated.

trevor
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Let f(x) = x2-7 and g(x) = x- 3
Find:
i. (f º g )(x) [2]
ii. (g º f) (x) [2]
iii. f-1 (x) = g-1(x)
 
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trevor said:
Let f(x) = x2-7 and g(x) = x- 3
Find:
i. (f º g )(x) [2]
ii. (g º f) (x) [2]
iii. f-1 (x) = g-1(x)

Hi trevor. What have you tried so far? :)
 
Joppy said:
Hi trevor. What have you tried so far? :)

I am clueless
 
(f o g)(x) means f(g(x)). That means, you replace the value in f(x) with g(x), thus your x2 - 7 will become (g(x))2 - 7. Can you continue from here?
 

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