Factor in equation (3.49) of Peskin and Schroeder

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The discussion centers on the 1/2 factor in the exponential of Eq. (3.49) in Peskin and Schroeder, specifically regarding the Lorentz boost transformation of a spinor. The confusion arises from the relationship between the rapidity and the parameters in the equation, particularly the interpretation of ω_{03}. The contributor realizes that the correct formulation involves summing over indices, which clarifies the discrepancy between their calculations and the textbook's factor. This summation is crucial to arriving at the correct exponent in the transformation. Ultimately, understanding the summation resolves the initial misunderstanding about the factor in the equation.
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My question concerns the 1/2 factor in the exponential of Eq. (3.49) of Peskin and Schroeder.

This equation concerns the Lorentz boost transformation of a spinor along the z-axis (or 3-direction).

According to Eq. (3.26):

S^{03} = -\frac{i}{2}\begin{bmatrix}\sigma^3 & 0 \\0 & -\sigma^3\end{bmatrix}

and Eq. (3.30):

\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{03} S^{03})

Combining these two expressions and using the infinitesimal boost (according to Eq. (3.48) and Eq. (3.21)): \omega_{03} = \eta (here \eta is the rapidity):

\Lambda_{1/2} = exp(-\frac{1}{4}\eta \begin{bmatrix}\sigma^3 & 0 \\0 & -\sigma^3\end{bmatrix})

My problem is that Peskin and Schroeder have a 1/2 factor where my simple substitution gives a 1/4?

Am I misinterpresting the meaning of \omega_{03}? I am assuming that \eta = \beta (v/c) from my understanding of Eq. (3.21)... this might be a problem?!?

Thanks for your help!
 
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jmlaniel said:
[...] and Eq. (3.30):

\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{03} S^{03})
In my version of P&S, eq(3.30) is
$$
\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{\mu\nu} S^{\mu\nu})
$$
and you must sum over ##\mu, \nu##. So you need an exponent involving
$$
(\omega_{03} S^{03} + \omega_{30} S^{30})
$$
Is that enough for you to figure out the rest...?
 
Thanks Strangerep! I just completely forgot the summation over the indices... That was also enough for me to figure out the rest!
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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