Factor Theorem: Solving a^5-32

  • Thread starter Thread starter Rowah
  • Start date Start date
  • Tags Tags
    Factoring
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
Rowah
Messages
17
Reaction score
0
Simple Factoring Problem

How do I factor [tex]a^5-32[/tex]?

It isn't a difference of cubes or even a difference of squares :(

By the way, we're currently learning the factor theorem.
 
Last edited:
Physics news on Phys.org
let f(a)= [tex]a^5-32[/tex] .when x=2,f(a)=0 so a-2 is a factor of the funtion. suppose you know how to carry on since you learned factor theorem?
 
Use the rule [tex]a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b+a^{n-3}b^2+\cdots+ab^{n-2}+b^{n-1}), n \in \textbf{N}[/tex].
 
Cool, I understand now, thanks, "a" messed me up, I didn't know you could do f(a), I thought it was only f(x).
 
Last edited: