Factor Theorem: Solving a^5-32

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Homework Help Overview

The discussion revolves around factoring the polynomial expression a^5 - 32, with participants referencing the factor theorem and exploring different factoring techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the factoring of a^5 - 32, noting it does not fit typical forms like difference of cubes or squares. Some participants suggest using the factor theorem and polynomial identities to find factors.

Discussion Status

Participants are engaging with the problem, with some offering insights into the factor theorem and polynomial rules. There is an acknowledgment of different notations (f(a) vs. f(x)), indicating a productive exchange of ideas.

Contextual Notes

The original poster mentions that they are currently learning the factor theorem, which may influence their understanding and approach to the problem.

Rowah
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Simple Factoring Problem

How do I factor [tex]a^5-32[/tex]?

It isn't a difference of cubes or even a difference of squares :(

By the way, we're currently learning the factor theorem.
 
Last edited:
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let f(a)= [tex]a^5-32[/tex] .when x=2,f(a)=0 so a-2 is a factor of the funtion. suppose you know how to carry on since you learned factor theorem?
 
Use the rule [tex]a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b+a^{n-3}b^2+\cdots+ab^{n-2}+b^{n-1}), n \in \textbf{N}[/tex].
 
Cool, I understand now, thanks, "a" messed me up, I didn't know you could do f(a), I thought it was only f(x).
 
Last edited:

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