Factoring e^x in a Complex Equation: Tips and Tricks

[cscott]

$$e^{2x} - 3e^{x + 1} + 2e^{2} = 0$$

I've been staring at this for the past while I can't solve it for x...

The only thing I can think of doing is factoring out $e^{x}$

 

[StatusX]

Try setting u=e^x. Then you'll have a quadratic equation for u.

 

[cscott]

Damn, thanks.