Factoring x2+4 and Special Cubed Theorems: Homework Help

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Homework Help Overview

The discussion revolves around factoring the expression x² + 4 and exploring special theorems related to cubic expressions. Participants are examining the implications of using imaginary numbers in factoring and recalling formulas for the sum and difference of cubes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the factorization of x² + 4, noting the necessity of imaginary numbers for real number factorization. There is also a mention of the sum and difference of cubes formulas. A new question is raised regarding the factorization of a limit expression, with uncertainty about whether factoring is necessary.

Discussion Status

The discussion is active, with participants providing insights into the factorization of x² + 4 and sharing relevant formulas. Questions about the need for factoring in the limit expression indicate ongoing exploration of the topic.

Contextual Notes

Participants are considering the use of imaginary numbers in their factorization attempts and questioning the necessity of factoring in the context of limits. There is a reference to evaluating expressions at specific points, which may influence the discussion on factoring.

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Homework Statement



can u factor x2+4
and can't seem to remember the the difference of cubes and isn't there another special cubed theorem.

Homework Equations





The Attempt at a Solution

 
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hockeyfghts5 said:

Homework Statement



can u factor x2+4
and can't seem to remember the the difference of cubes and isn't there another special cubed theorem.

It can be factored but it won't be factored with real numbers. You'd need to introduce the imaginary constant,i, such that i2=-1 and use that to factor.
 
x2 + 4 = (x + 2i)(x - 2i), where i is the imaginary unit rock.freak667 mentioned.
Here are the sum and difference of cubes formulas:
x3 + a3 = (x + a)(x2 - ax + a2)
x3 - a3 = (x - a)(x2 + ax + a2)
 
thanks, so i have another question if someone can help me.

lim x3-62+11x-6
x->-1 x3-4x2-19x +14
i can't seem how to factor the top out if i even need to do that or the bottom
 
hockeyfghts5 said:
thanks, so i have another question if someone can help me.

lim x3-62+11x-6
x->-1 x3-4x2-19x +14
i can't seem how to factor the top out if i even need to do that or the bottom

Why would you need to factor it? Did you evaluate it at x=-1? Was it in the indeterminate form 0/0?
 
If the numerator, or denominator, goes to zero when x = 1, then (x-1) is a factor.

You can factor it out by dividing (x-1) into the numerator, say, in the style of long-division.
 

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