Factorize the polynomial a^3 + b ^3 + c^3 - 3abc

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SUMMARY

The polynomial a^3 + b^3 + c^3 - 3abc can be factorized using the identity that states it equals (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc). The first factor, (a + b + c), is straightforward, while the second factor, a^2 + b^2 + c^2 - ab - ac - bc, is a quadratic expression that does not factor further into linear components. Tools such as Maple and Mathematica confirm this factorization, indicating that the expression is simplified as much as possible.

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Homework Statement



factorise: a^3 + b^3 + c^3 - 3abc

Homework Equations





The Attempt at a Solution



I had a few random attempts and found that (a + b + c) is factor, and then dividing the original equation by (a + b + c) yeilds a^2 + b^2 + c^2 - ab - ac - bc

I can't figure out how to factorise this quadratic. I tried solving for A and it either doesn;t work, or I did it wrong lol. short of trying a zillion different factors (i'd rather not, I'd prefer a more elegant solution), what can I do?

thanks.
 
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I don't think you can. I stuck it into both maple and mathematica and they return the same factors as you have found.
 
so I've factorised it as far as I can? :S

if so its a stupid problem lol. wouldve thought it would've given linear factors.
 

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