Factorizing 2ab - 4ac + bd - 2de | Help Appreciated

[Dave06]

Factorize the following

2ab - 4ac + bd - 2de

cant get this at all

any help is appreciated

 

[mathman]

Factorize the following

2ab - 4ac + bd - 2de

cant get this at all

any help is appreciated

Immediately you can get 2a(b-2c)+d(b-2e).

If you have a typo (e should be c?), then you have (2a+d)(b-2c).

 

[Dave06]

im afraid not

the question asks

Factorise the following expressions by extraction or grouping of the common factors

2ab - 4ac + bd - 2de

 

[HallsofIvy]

Then the best you can do is, as mathman said, 2a(b- 2c)+ d(b- 2e).