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Failing at projection question

  1. Nov 21, 2008 #1
    let pf(x)= sum( from i=1 to k) <x, ui>ui, show pf is a projection.

    Ive tried to show this fact myself but i failed. Please some one help me out. thanks

    Note ui = u1...un an orthogonal basis of V where V is a vector space.
  2. jcsd
  3. Nov 22, 2008 #2
    Re: projection

    Welcome to PF, reha.

    The usual procedure in showing that a given function is a projection, is to verify that is satisfies the definition of a projection. (By the way, that's true for many other things as well.)

    So, what's the definition of a projection in a vector space?
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